The antiderivative of 1/x is ln(x), not ln |x

2 points by max__dev 230 days ago | 2 comments

NoahZuniga 230 days ago |

Sir what you wrote down is equivalent to integral 1/x = ln|x| if x > 0 else ln|x| + pi*i

gus_massa 229 days ago | |

1/x = ln|x| + C if x > 0

ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)

In reals ln|x| is fine.

NoahZuniga 230 days ago |

Sir what you wrote down is equivalent to integral 1/x = ln|x| if x > 0 else ln|x| + pi*i

gus_massa 229 days ago | |

1/x = ln|x| + C if x > 0

ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)

In reals ln|x| is fine.