Success = (number of attempts) × (probability of success each time)

3 points by adletbalzhanov 15 days ago | 2 comments

apothegm 15 days ago |

I think you mean (1-(1-prob[success])^numAttempts).

adletbalzhanov 15 days ago | |

Touché, you're right. The point still stands though: run the program more times

apothegm 15 days ago |

I think you mean (1-(1-prob[success])^numAttempts).

adletbalzhanov 15 days ago | |

Touché, you're right. The point still stands though: run the program more times